context stringlengths 11 9.12k | question stringlengths 0 1.06k | SQL stringlengths 2 4.44k | source stringclasses 28
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CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update d... | Among the payments made by Mary Smith, how many of them are over 4.99? | SELECT COUNT(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND T1.amount > 4.99 | bird |
CREATE TABLE movie_3 (film_id integer, title text, description text, actor_id integer, first_name text, last_name text, last_update datetime, address_id integer, address text, address2 text, district text, city_id integer, postal_code text, phone text, last_update datetime, category_id integer, name text, last_update d... | What is the average amount of money spent by a customer in Italy on a single film rental? | SELECT AVG(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy' | bird |
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